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无穷级数的重排

2012-07-03 21:42:40| 分类：数学专题讲解 | 标签： |举报 |字号大中小订阅

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m:=8:

a:=n->1/(2*n-1)-sum(1/(2*m*n-2*k),k=0..m-1);

Sum(a(n),n=1..infinity)=sum(a(n),n=1..infinity):

evalf(%);

m:=8:

a:=n->sum(1/(2*m*n-2*k-1),k=0..m-1)-1/(2*n);

Sum(a(n),n=1..infinity)=sum(a(n),n=1..infinity);

evalf(%);

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